You can write your question in contact us form and Math teacher will answer your question.

Kamiya Gulati India hi..can u give me solution of math puzzle 3...not only answers,,how they are solve.. 19 Mar 1242.109.16.198 Hi Kamiya 1) There are 40 coins in a bag, consisting of $ 5 and $ 2 coins. If the total amount is Rs. 140, how many $ 2 and $ 5 coins are there in the bag? Ans : $5 = x so $2 = 40 -x 5x + 2(40 - x) = 140 5x + 80 -2x = 140 3x = 140 -80 3x = 60 x = 20 So 20 each. 2) Four years ago, the average age of A and B was 18 years. At present the average age of A, Band C is 24 years. What would be the age of C after 8 years? Ans : (A + B + C )/3 = 24 A +B + C = 72 4 years ago (A - 4 + B - 4 )/2 = 18 A + B - 8 = 36 A + B = 44 C = 72 -44 C = 28 After 8 years C will be 36 years Similarly you can solve the rest. Anita |

Yousifmahboubakrfs_empire Iraq Q/ Graph f(x)= x-5/(x-5)(x+6) x-5 f(x) = -------- (x-5)(x+6) D = R/{5,-6} But Can't We Write it Like 1 f(x) = -------- (x+6) D = R/{-6} in the first function we couldn't use (x=5) but when we divide by (x-5) we could use (x=5) is that possible ! , or we cant simplify the function ? 17 Mar 12109.224.28.248 Hi, This is Anita,your Math guide. Your question is how to graph f(x)= x-5/(x-5)(x+6) if the denominator's degree is greater (by any margin), then you have a horizontal asymptote at y = 0 (the x-axis) The domain is the set of all x-values that I'm allowed to use. The only values that could be disallowed are those that give me a zero in the denominator. So I'll set the denominator equal to zero and solve. (x -5)(x + 6) =0 x -5 = 0 or x + 6 = 0 x = 5 or x = -6 vertical asymptote is x = - 6 , 5 Domain = x not equal to -6, 5 You can see the attachment of this graph. Answer |

Manisha TapaswiIndia prove that (tanθ/1-cotθ)+cotθ/1-tanθ)=1+tanθ+cotθ 22 Dec 11220.225.70.2 Hi Manisha Please find the answer of your question. If you have any doubt, you can ask me. Answer Manusha Gokhale :writetogokhale@gmail.com (12/22/11) To me Thanks a lot. ... I misssed last step and got into tan2θ+1=sec2θ and goofed it it up. So I got the answer as 1+sec@.Cosec@ Here is another ax ^{2}+bx+c=0 is the equation. Sum of its roots are equal to the sum ofthe squares of the their reciprocal. Prove that bc ^{2}, ca^{2},ab^{2} are in
AP. Answer |

Question asked by Prateek Verma on YouTube √(540.563) = 23.25 |

Home Page