As all the sides of rhombus are equal so the perimeter of rhombus is same as that of square.

1) The side of a rhombus is 18 cm . Find its perimeter.

Perimeter of Rhombus = 4 x side

⇒ = 4 x 18

&rArr = 72 cm

∴ Perimeter of Rhombus = 72 cm.

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2) Find the area of a rhombus having each side equal to 13 cm and one of whose diagonal is 24 cm.

Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.

AC = 24 ⇒ AO = 12

Let BO = x and AB = 13 cm (given)

By Pythagorean theorem

c

13

x

x

x = 5 cm

BO = 5 cm

Diagonal BD = 2 x 5 = 10 cm.

Area = ½ x [ product of diagonals]

= ½ x 24 x 10

Area = 120 sq.cm

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3) If the area of a rhombus is 24 sq.cm and one of its diagonal is 4 cm find the length of the other diagonal.

Area = ½ x d1 x d2

24 = ½ x 4 x d2

24 = 2 x d2

d2 = 24/2

d2 = 12 cm

• Perimeter and Area of Irregular Shape

• Area and Perimeter of the Rectangle

• Area of Square (perimeter of square)

• Perimeter of Parallelogram(Area of Parallelogram)

• Area of Rhombus(Perimeter of rhombus)

• Area of Trapezoid (Trapezium)

• Triangle Area (Perimeter of triangle)

• Herons Formula

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