$\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}$

1) Show that vectors PQ and RS are equivalent vectors.Solution: To show that the two vectors are equivalent, we will find the magnitude of each vectors.$\left \| \vec{PQ} \right \|=\sqrt{(4-1)^2 +(4 - 2)^2}$ = $\sqrt{13}$ $\left \| \vec{RS} \right \|=\sqrt{(3-0)^2 +(2 - 0)^2}$ = $\sqrt{13}$ Moreover both the line segments have same direction since both are directed upward. Both the vectors have same magnitude $\sqrt{13}$ from the distance formula. $\left \| \vec{PQ} \right \| = \left \| \vec{RS} \right \|$ are equivalent vectors. |

As the two vectors are equal,

So, $\left \| \vec{AB} \right \|= \left \| \vec{CD} \right \|$

$\sqrt{(1-4)^+(-2 +1)^2} = \sqrt{(a - 0)^2 + (-1 -0)^2}$

$\sqrt{(9+1)} = \sqrt{(a^{2} +1}$

10 = $a^{2}$ +1

9= $a^{2}$

a =$ \pm $3

2)Given that two endpoints of two vectors are P(-1, 4), Q(5, 2) and R(1, -2), S(4, -5). Check whether the two vectors $\left \| \vec{PQ} \right \|$ and $\left \| \vec{RS} \right \|$ are equal vectors?

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