In this section, we will discuss kite and its theorems.

In kite, adjacent sides are equal and long diagonal bisect the small diagonal at right angle.All interior angles are acute angles.

Proof :

Statements |
Reasons |

1)AB ≅ AD | 1) Given |

2) BC ≅ CD | 2) Given |

3) AC ≅ AC | 3) Reflexive (common side) |

4) ΔABC ≅ ΔADC | 4) SSS Postulates |

5) ∠BAE ≅ ∠DAE | 5) CPCTC |

6) ΔABD is an Isosceles triangle. | 6) By property of an isosceles triangle. |

7) ∠ABE ≅ ∠ADE | 7) Property of isosceles triangle. |

8) ΔABE ≅ ΔADE | 8) ASA postulate. |

9) ∠AEB ≅ ∠AED | 9) CPCTC |

10)∠AEB +∠AED = 180 | 10) Linear pair angles are supplementary. |

11) 2∠AEB = 180 | 11) Addition property |

12) ∠AEB = 90 | 12) Division property |

13) AC ⊥ BD and AE ⊥ BD |
13) By property of perpendicular. |

Proof :

Statements |
Reasons |

1)AB ≅ AD | 1) Given |

2) BC ≅ CD | 2) Given |

3) AC ≅ AC | 3) Reflexive (common side) |

4) ΔABC ≅ ΔADC | 4) SSS Postulates |

5) ∠ABC ≅ ∠ADC | 5) CPCTC |

______________________________________________________________

In a kite, ABCD,AB = x + 2 , BC = 2x + 1. The perimeter of kite is 48cm. Find x and also find the length of each side.

As we know that, adjacent sides in a kite are equal.

∴ AB = AD and BC = CD.

Perimeter = sum of all the sides

P = AB + BC + CD + AD

48 = x + 2 + 2x + 1 + x + 2 + 2x + 1

48 = 6x + 6

⇒ 6x = 48 -6

∴ 6x = 42

x = 42/6

x = 7

∴ AB = AD = x + 2 = 7 + 2 = 9cm

and BC = CD = 2x + 1 = 2(7) + 1 = 14 + 1 = 15 cm

• Introduction to Quadrilateral

• Types of Quadrilateral

• Properties of Quadrilateral

• Parallelogram and its Theorems

• Rectangle and its Theorems

• Square and its Theorems

• Rhombus and its Theorems

• Trapezoid (Trapezium)and its Theorems

• Kite and its Theorems

• Mid Point Theorem

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