The parts of Circle are Diameter,Radius,Arc and Sector.

**Relation between diameter and radius**

Diameter = 2 x radius

Or radius = r = d / 2.

**Circumference ( C ) :** The length of a boundary of a circle.

C = 2 Πr

Or C = Π D

________________________________________________________________

**Examples **

1) Radius = 4 cm, find the diameter.

**Solution :**

Diameter = 2 x radius

⇒ Diameter = 2 x 4

⇒ Diameter = 8 cm.

________________________________________________________________

2) Diameter = 6.4 cm, find the radius.

**Solution : **

radius = r = d / 2.

⇒ radius = 6.4/2

⇒ radius = 3.2 cm

_________________________________________________________________

2)If the radius of circle is 1.5 cm then find the diameter and the circumference.

**Solution :**

Diameter = D = 2 r

D = 2 x 1.5

D = 3 cm.

Circumference = C = &pie;D

C = 3.14 x 3

C = 9.42 cm

________________________________________________________________

Some more parts of circle are as follows:

**Arc :** A part of a circle between any two points on the circle.

There are two types of arcs 1) Minor arc 2) Major arc.

Here PQR is the minor arc and PR is a major arc.

As arc is a part of a circle so,

**Length of a minor arc = Π rθ / 180 **

Length of major arc = 2Πr - Π rθ / 180

________________________________________________________________

** Examples **

1) Find the length of arc of radius 6 cm and angle formed by the two radii is 60^{0} .

** Solution :**

r = 6 cm , θ = 60^{0} and Π = 3.14

Length of a minor arc = Π rθ / 180

Length of a minor arc = ( 3.14 x 6 x 60 ) / 180

Length of arc = 6.28 cm

________________________________________________________________

2)**Sector :** The region enclosed by two radii and an arc.

Area ( minor sector ) = Πr^{2} θ / 360

Area ( major sector) = Πr^{2} - Πr ^{2} θ / 360

________________________________________________________________

**Example :** Find the area of sector whose radius is 8 cm , angle θ 30 ^{0} and Π = 3.14.

**Solution : **

r = 8 cm , θ = 30^{0} and Π = 3.14

Area of sector = Πr^{2} θ / 360

Area = (3.14 x 8^{2} x 30 ) / 360

Area of sector = 16.75 cm^{2}

**Circles **

• Circles

• Parts of Circle

• Arc and Chords

• Equal Chords of a Circle

• Arc and Angles

• Cyclic Quadrilaterals

• Tangent to Circle

Home Page

Diameter = 2 x radius

Or radius = r = d / 2.

C = 2 Πr

Or C = Π D

________________________________________________________________

1) Radius = 4 cm, find the diameter.

Diameter = 2 x radius

⇒ Diameter = 2 x 4

⇒ Diameter = 8 cm.

________________________________________________________________

2) Diameter = 6.4 cm, find the radius.

radius = r = d / 2.

⇒ radius = 6.4/2

⇒ radius = 3.2 cm

_________________________________________________________________

2)If the radius of circle is 1.5 cm then find the diameter and the circumference.

Diameter = D = 2 r

D = 2 x 1.5

D = 3 cm.

Circumference = C = &pie;D

C = 3.14 x 3

C = 9.42 cm

________________________________________________________________

Some more parts of circle are as follows:

There are two types of arcs 1) Minor arc 2) Major arc.

Here PQR is the minor arc and PR is a major arc.

As arc is a part of a circle so,

Length of major arc = 2Πr - Π rθ / 180

________________________________________________________________

1) Find the length of arc of radius 6 cm and angle formed by the two radii is 60

r = 6 cm , θ = 60

Length of a minor arc = Π rθ / 180

Length of a minor arc = ( 3.14 x 6 x 60 ) / 180

Length of arc = 6.28 cm

________________________________________________________________

2)

Area ( minor sector ) = Πr

Area ( major sector) = Πr

________________________________________________________________

r = 8 cm , θ = 30

Area of sector = Πr

Area = (3.14 x 8

Area of sector = 16.75 cm

• Circles

• Parts of Circle

• Arc and Chords

• Equal Chords of a Circle

• Arc and Angles

• Cyclic Quadrilaterals

• Tangent to Circle