In this section we will discuss about Perimeter and Area of Irregular Shape.

Perimeter : It is the length of the boundary of a closed figure.

In other words, we can say that the Perimeter is the total length of the boundary or sum of all sides.

It is measured in m (meter) , cm(centimeter) , Km (kilometer ) and miles.

** Examples on Perimeter and Area of Irregular Shape : **

1)

Perimeter= AB + BQ + QC + CD + DS + SE + EF + FR + RG + GH + HP + PA

= 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3

= 28 cm

_________________________________________________________________

2) Find the Perimeter of the given figure.

**Solution : **

Perimeter = AB + BC + CD + DE + EF + FA

= 10 cm + 8 cm + 2 cm + 4 cm + 8 cm + 2 cm

= 34 cm

_________________________________________________________________

3) Calculate the perimeter of the following figure:

**Solution : **

Perimeter = 2 + 2 + 2 + 2 + 2 = 10 cm

_________________________________________________________________

4) Find the area of figure.

**Solution :**

Area of the figure = Area of I + Area of II + Area of III

Now, Area of figure I = 3.4 x 2.5

= 8.5 cm^{2}

Area of figure II = (6 - 3)x(3.4 - 2)

= 3 x 1.4

= 4.2 cm^{2}

Area of figure III = 3 x 1

= 3 cm^{2}

Total area = 8.5 + 4.2 + 3

= 15.7 cm^{2}

**Mensuration : Area and Perimeter **

• Perimeter and Area of Irregular Shape

• Area and Perimeter of the Rectangle

• Area of Square (perimeter of square)

• Perimeter of Parallelogram(Area of Parallelogram)

• Area of Rhombus(Perimeter of rhombus)

• Area of Trapezoid (Trapezium)

• Triangle Area (Perimeter of triangle)

• Herons Formula

From Area of Irregular shape to Mensuration page

From Area of Irregular Shape to Home Page

Perimeter : It is the length of the boundary of a closed figure.

In other words, we can say that the Perimeter is the total length of the boundary or sum of all sides.

It is measured in m (meter) , cm(centimeter) , Km (kilometer ) and miles.

1)

Perimeter= AB + BQ + QC + CD + DS + SE + EF + FR + RG + GH + HP + PA

= 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3 + 1 + 3 + 3

= 28 cm

_________________________________________________________________

2) Find the Perimeter of the given figure.

Perimeter = AB + BC + CD + DE + EF + FA

= 10 cm + 8 cm + 2 cm + 4 cm + 8 cm + 2 cm

= 34 cm

_________________________________________________________________

3) Calculate the perimeter of the following figure:

Perimeter = 2 + 2 + 2 + 2 + 2 = 10 cm

_________________________________________________________________

4) Find the area of figure.

Area of the figure = Area of I + Area of II + Area of III

Now, Area of figure I = 3.4 x 2.5

= 8.5 cm

Area of figure II = (6 - 3)x(3.4 - 2)

= 3 x 1.4

= 4.2 cm

Area of figure III = 3 x 1

= 3 cm

Total area = 8.5 + 4.2 + 3

= 15.7 cm

• Perimeter and Area of Irregular Shape

• Area and Perimeter of the Rectangle

• Area of Square (perimeter of square)

• Perimeter of Parallelogram(Area of Parallelogram)

• Area of Rhombus(Perimeter of rhombus)

• Area of Trapezoid (Trapezium)

• Triangle Area (Perimeter of triangle)

• Herons Formula

From Area of Irregular Shape to Home Page