GeometryProof-1(Basic Proportionality Theorem)

In this section we will discuss geometryproof-1 which contains the proofs on basic proportionality theorems.
If the two lines are parallel then their intercepts are in proportion.
3) If DE || AQ and DE || AR. Prove that EF || QR.
Given : DE || OQ and DF || OR
Prove that : EF || QR.
Proof :

 Statements Reasons 1) DE || OQ 1) Given (ΔPOQ) 3) PE/EQ = PD/DO 3) Basic Proportionality Theorem 4) DF || OR 4) Given (ΔPOR) 5) PF/FR = PD/DO 5)Basic Proportionality Theorem 6) PE/EQ = PD/DO 6) From (2) and (4) (Transitivity) 7) EF || QR 7) Converse of Basic Proportionality Theorem

GeometryProof1
4) Given : A, B and C are the points on OP,OQ and OR respectively such that AB || PQ and AC || PR.

Given: AB || PQ and AC || PR.
Prove that : BC || QR
Proof :
 Statements Reasons 1) AB || PQ 1) Given (ΔOPQ) 3) OA/AP = OB/BQ 3) Basic Proportionality Theorem 4) AC || PR 4) Given (ΔOPR) 5) OA/AP = OC/CR 5)Basic Proportionality Theorem 6) OB/BQ = OC/CR 6) From (2) and (4) (Transitivity) 7) BC || QR 7) Converse of Basic Proportionality Theorem

5) In given figure, DE || BC and CD || EF. Prove that AD2 = AB x AF

Given : DE || BC and CD || EF
Prove that : AD2 = AB x AF
Proof :
 Statements Reasons 1) DE || BC 1) Given (ΔABC) 3) AB/AD = AC/AE 3) Basic Proportionality Theorem 4) FE || DC 4) Given (ΔADC) 5) AD/AF = AC/AE 5)Basic Proportionality Theorem 6) AB/AD = AD/AF 6) From (2) and (4) (Transitivity) 7) AD2 = AB x AF 7) Cross multiply

Geometry proofs
GeometryProof-1
GeometryProof 2
Proofs on Area of similar triangles
Pythagorean theorem

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