SSS Similarity
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SSS similarity : If the corresponding sides of two triangles are proportional, then the two triangles are similar.Given : Two triangles ABC and DEF such that
AB BC CA ---- = ------ = ------ DE EF FD |
Prove that : ΔABC ~ ΔDEF
Construction : Let P and Q be two points on DE and DF respectively such that DP = AB and DQ = AC. Join PQ.

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1) AB AC ---- = ------ DE DF |
1) Given |
2) DP DQ ---- = ------ DE DF |
2) As AB = DP and AC = DQ. By substitution |
3) PQ || EF | 3) By converse of basic proportionality theorem |
4) ∠DPQ = ∠E and ∠DQP = ∠F | 4) Corresponding angles |
5) ΔDPQ ~ ΔDEF | 5) By AA similarity |
6) DP PQ ---- = ------ DE EF |
6) By definition of similar triangles |
7) AB PQ ---- = ------ DE EF |
7) As DP = AB , by substitution |
8) PQ BC ---- = ------ EF EF |
8) From (1) (6) and (7) |
9) PQ = BC | 9) From (8) |
10) ΔABC ≅ ΔDPQ | 10) By S-S-S postulate |
11) ΔABC ~ ΔDEF | 11) From (5) and (10) |
Examples

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1) AB = 4; AC = 2;CB = 6; DE = 2; DF = 1; FE = 3 | 1) Given |
2) AB BC CA ---- = ------ = ------ DE EF FD |
2) Property of proportion |
3) ΔABC ~ ΔDEF | 3) By S-S-S-similarity |
1) In ΔPQR ~ ΔXYZ, PQ = 5cm, QR = 4cm and PR= 6m ,find XY, YZ and XZ.
2) In ΔABC, D and E are any points on AB and AC respectively, such that DE||BC. If AD=x cm, DB=x-2 cm, AE=x-1 cm, then find the value of x.
Criteria for Similarity
• AAA Similarity
• AA Similarity
• SSS Similarity
• SAS Similarity
• Practice on Similarity
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