Calculate the length of vector
Calculate the length of vector

Algebra Word Problems

We at ask-math believe that educational material should be free for everyone. Please use the content of this website for in-depth understanding of the concepts. Additionally, we have created and posted videos on our youtube.

We also offer One to One / Group Tutoring sessions / Homework help for Mathematics from Grade 4th to 12th for algebra, geometry, trigonometry, pre-calculus, and calculus for US, UK, Europe, South east Asia and UAE students.

Affiliations with Schools & Educational institutions are also welcome.

Please reach out to us on [email protected] / Whatsapp +919998367796 / Skype id: anitagovilkar.abhijit

We will be happy to post videos as per your requirements also. Do write to us.

Examples on Algebra Word Problems

1) The three angles in a triangle are in the ratio of 2:3:4. Find the measure of each angle.

Solution :
Let the ratio = x

As in the triangle, sum of all the three angles = 1800

2x + 3x + 4x = 180

9x = 180

X = 20

Each angle,

2x = 2( 20) = 400

3x = 3(20) = 600

4x = 4(20) = 800
_________________________________________________________________
2) The sum of 3 consecutive even numbers is 78. Find the numbers.

Solution :
Let the 3 consecutive even numbers are x, x+2 and x+4.

Therefore,

x + (x + 2) + (x + 4) = 78

Or 3x + 6 = 78

Or 3x = 78 – 6 = 72

Or x = 24 (Divide both sides by 3)

So the three numbers are 24,26,18.
_________________________________________________________________
3) There are 650 students in a school. If the number of girls is 106 more than the boys, how many boys are there in the school?

Solution :
Let the number of boys = x

Then, number of girls = x + 106

x + (x + 106) = 650 (Given in the question)

Or 2x + 106 = 650

Or 2x = 650 – 106 = 544

Or x = 272

Hence, the number of boys = 272

And, the number of girls = (x + 106)

= 272 + 106

= 378
_________________________________________________________________
4) I have a total of $300 in coins of denomination $1, $2 and $5. The number of $2 coins is 3 times the number of $5 coins. The total number of coins is 160. How many coins of each denomination are with me?

Solution
Let $5 coin = x
∴ $2 coins = 3x
Total number of coins = 160
So, $1 coin = 160 - (x +3x)= 160 -4x
Total money = $300
∴ 5(x) + 2(3x) + 1(160 -4x)=300
⇒ 5x + 6x + 160 - 4x = 300
⇒ 11x -4x + 160 =300
⇒ 7x + 160 =300
⇒ 7x = 300 -160
⇒ 7x = 140
So, $5 coins are 20
$2 coins = 3x = 3(20)=60
$1 coins = 160 -(20 + 60)
$1 coins = 80
________________________________________________________________________

Linear Equation in One Variable

Linear Equation in One Variable
Algebraic Equations with Fractions
Algebra Word Problems
Algebra Rate (upstream and downstream) Problems
Algebra Age Problems
Algebra Digit Problems

Home Page