Arc and Chords

We at ask-math believe that educational material should be free for everyone. Please use the content of this website for in-depth understanding of the concepts. Additionally, we have created and posted videos on our youtube.

We also offer One to One / Group Tutoring sessions / Homework help for Mathematics from Grade 4th to 12th for algebra, geometry, trigonometry, pre-calculus, and calculus for US, UK, Europe, South east Asia and UAE students.

Affiliations with Schools & Educational institutions are also welcome.

Please reach out to us on [email protected] / Whatsapp +919998367796 / Skype id: anitagovilkar.abhijit

We will be happy to post videos as per your requirements also. Do write to us.

Arc and Chords : Arc is a part of a circle and chord is a segment whose end points are on the circle.

Some Definitions related to Arc - Chords are :

Congruent circles : Two circles are said to be congruent if and only if their radii are equal.

Congruent arc : Two arcs of a circle are said to be congruent if and only if they have the same degree of measure.

Some results on congruent Arc and chords

1) If two arcs of a circle are congruent, then corresponding chords are equal.

If arc PQ = arc RS then chord PQ = chord RS

Converse of the above is also true.

If chord PQ = chord RS then arc PQ = arc RS.
2) The perpendicular from the center of a circle to a chord bisects the chord.

If OM ⊥ PQ then MP = MQ

Converse of the above is also true.

If MP = MQ then OM ⊥ PQ.

3) If two chords of a circle AB and AC of a circle with center O are such that center O lies on the bisector of ∠BAC, then AB = AC ( chords are equal ).

4) If two circles intersect in two points, then the line through the centers is perpendicular bisector of the common chord.

OP ⊥ bisector of AB
Some solved problems on above theorems :

1) Line l intersect two concentric circles whose common center is ‘O’ at the points A,B, C and D. Show that AB = CD.

Given : O is the center of two concentric circles.
Line l intersect two circles in A,B, C and D.

Prove that : AB = CD

Construction : OM ⊥ BC and AD

1) OM ⊥ BC 1) By construction
2) BM = CM 2) Perpendicular drawn from the center bisects the chord.
3) OM ⊥ AD 3) By construction
4) AM = DM 4) Perpendicular drawn from the center bisects the chord.
5) AM - BM = DM - CM 5) Subtraction property (4) and (2)
6) AB = CD 6) Subtraction property
2) O is the center of the circle of radius 5 cm. OP ⊥ AB,OQ ⊥ CD, AB || CD, AB = 6 cm and CD = 8 cm. Find PQ.
Solution :
Join OA and OC

As perpendicular drawn from the center, bisects the chord AB and CD at P and Q respectively.
AP = PB = ½ AB = 3 cm
And CQ = QD = ½ CD = 4 cm
In right triangle OAP, by Pythagorean theorem
OA2 = OP2 + AP2
52 = OP2 + 32
⇒ OP2 = 52 - 32
⇒ OP2 = 25 – 9 = 16
⇒ OP = 4 cm
In right triangle OCQ, by Pythagorean theorem
OC2 = OQ2 + CQ2
⇒ 52 = OQ2 - 42 = 9
⇒ OQ = 3
∴ PQ = PO – QO
PQ = 4 -3
PQ = 1 cm.

Parts of Circle
Arc and Chords
Equal Chords of a Circle
Arc and Angles
Cyclic Quadrilaterals
Tangent to Circle

Home Page

Russia-Ukraine crisis update - 3rd Mar 2022

The UN General assembly voted at an emergency session to demand an immediate halt to Moscow's attack on Ukraine and withdrawal of Russian troops.