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Kamiya Gulati

hi..can u give me solution of math puzzle 3...not only answers,,how they are solve..
19 Mar 1242.109.16.198

Hi Kamiya
1) There are 40 coins in a bag, consisting of $ 5 and $ 2 coins. If the total amount is Rs. 140, how many $ 2 and $ 5 coins are there in the bag?
Ans : $5 = x so $2 = 40 -x
5x + 2(40 - x) = 140
5x + 80 -2x = 140
3x = 140 -80
3x = 60
x = 20
So 20 each.

2) Four years ago, the average age of A and B was 18 years. At present the average age of A, Band C is 24 years. What would be the age of C after 8 years?
Ans : (A + B + C )/3 = 24
A +B + C = 72
4 years ago
(A - 4 + B - 4 )/2 = 18
A + B - 8 = 36
A + B = 44
C = 72 -44
C = 28
After 8 years C will be 36 years
Similarly you can solve the rest.



Q/ Graph f(x)= x-5/(x-5)(x+6) x-5 f(x) = -------- (x-5)(x+6) D = R/{5,-6} But Can't We Write it Like 1 f(x) = -------- (x+6) D = R/{-6} in the first function we couldn't use (x=5) but when we divide by (x-5) we could use (x=5) is that possible ! , or we cant simplify the function ?
17 Mar 12109.224.28.248

This is Anita,your Math guide.
Your question is how to graph
f(x)= x-5/(x-5)(x+6)
if the denominator's degree is greater (by any margin), then you have a horizontal asymptote at y = 0 (the x-axis)
The domain is the set of all x-values that I'm allowed to use. The only values that could be
disallowed are those that give me a zero in the denominator. So I'll set the denominator equal to zero and solve.
(x -5)(x + 6) =0
x -5 = 0 or x + 6 = 0
x = 5 or x = -6
vertical asymptote is
x = - 6 , 5

Domain = x not equal to -6, 5
You can see the attachment of this graph.

Manisha Tapaswi

prove that (tanθ/1-cotθ)+cotθ/1-tanθ)=1+tanθ+cotθ
22 Dec 11220.225.70.2

Hi Manisha
Please find the answer of your question. If you have any doubt, you can ask me.

Manusha Gokhale :[email protected] (12/22/11)
To me
Thanks a lot. ...
I misssed last step and got into tan2θ+1=sec2θ and goofed it it up. So
I got the answer as [email protected]@
Here is another
ax2+bx+c=0 is the equation. Sum of its roots are equal to the sum of
the squares of the their reciprocal. Prove that bc2, ca2,ab2 are in AP.


Question asked by Prateek Verma on YouTube

√(540.563) = 23.25

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