As cosec is a reciprocal of sine function so for some values this function is discontinuous. There are vertical asymptotes in cosec graph.The asymptote repeats after every π units.

We know that csc x ≤ -1 or csc ≥ 1.

First, we graph y = sin x and then y = csc x immediately below it. Compare the y-values in each of the 2 graphs and assure yourself they are the reciprocal of each other.The x-intercept of y=sin x and the asymptotes of y = csc x are same. The cosec graph is a ∪ shaped graph. There is no amplitude for this graph.

y= csc(bx + c)

b and c are responsible for phase shift.

Phase shift means the graph will shift towards left or right side from its normal position.The displacement of the graph is based on bx + c. Make this equal to zero and solve for x.

bx + c = 0

bx = -c

x = -c/b So the

For y = sin (x +2)

Phase shift is -c/b where c = 2 and b = 1(coefficient of x).

∴ Phase shift = -2

so the sine graph will shift 2 units to left side.

So the csc graph will also shift towards left by 2.

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