# Cube by Column method

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For finding the cube by column method use the following formula:-
(a + b)3 = a3 + 3a2b + 3ab2 + b3
In this method, first find the 2 digits of a number.

Example:
1) 323, so here the two digits are 3 and 2.
2) 463, two digits are 4 and 6.

Examples:-

1) Find 243.
Solution: Here two digits are 2 and 4.
a = 2, and b = 4. By using the column-method:-
 Column I Column II Column III Column IV a3 3 x a2 x b 3 x a x b2 b3 23 = 8 + 5 3 x 22 x 4 = 48 + 10 3 x 2 x 42 = 96 + 6 43 = 64 13 58 102 4 13 8 2 4

∴ 243 = 13824
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2) Find 423.
Solution: Here two digits are 4 and 2.
a = 4, and b = 2. By using the column-method:-

 Column I Column II Column III Column IV a3 3 x a2 x b 3 x a x b2 b3 43 = 64 + 10 3 x 42 x 2 = 96 + 4 3 x 4 x 22 = 48 + 0 23 = 8 74 100 48 8 74 0 8 8

∴ 423 = 74088

Cube - Cube Roots

Cube of Numbers
Perfect- Cube
Properties of - Cube
Cube by Column method
Negative numbers-cube
Cube - of Rational numbers
Cube-Root
Finding cube-root by Prime Factorization
Cube-root of Rational numbers
Estimating cube-root

From column method to Exponents