Cyclic Quadrilaterals
A quadrilateral is called Cyclic Quadrilaterals if its all vertices lie on a circle.
It has some special properties which other quadrilaterals, in general, need not have. We shall state and prove these properties as theorems. They are as follows :
1) The sum of either pair of opposite angles of a cyclic- quadrilateral is 180
0
OR
The opposite angles of cyclic quadrilateral are supplementary.

∠A + ∠C = 180
0 and ∠B + ∠D = 180
0
Converse of the above theorem is also true.
If the opposite angles are supplementary then the quadrilateral is a cyclic-quadrilateral.
2) If one side of a cyclic-quadrilateral is produced, then the exterior angle is equal to the interior opposite angle.

ABCD is a cyclic-quadrilateral then ∠CBE = ∠ADC
3) If two non-parallel sides of trapezoid ( trapezium ) are equal, it is cyclic.

If AD = CB then the trapezoid ABCD is a cyclic-quadrilateral.
Some solved examples on the above results
1) ABCD is a cyclic-quadrilateral; O is the center of the circle. If ∠BOD = 160
0, find the measure of ∠BPD and ∠BCD.
Solution :

∠BOD = 160
0 ( given and it’s a central angle )
∴ ∠BAD = ½ ∠BOD = 80
0
As ABCD is a cyclic-quadrilateral,
⇒ ∠BAD + ∠BPD = 180
0
80 + ∠BPD = 180
⇒ ∠BPD = 100
0
⇒ ∠BCD = 100
0 ( Angles in the same segment )
_________________________________________________________________
2) ABCD is a cyclic-quadrilateral. AB and DC are produced to meet in E. Prove that ΔEBC ~ ΔEDA.
Solution :
Given : ABCD is a cyclic-quadrilateral.
Prove that : ΔEBC ~ ΔEDA.
Statements |
Reasons |
1) ABCD is cyclic-quadrilateral. |
1) Given |
2) ∠EBC = ∠EDA |
2) Exterior angle in a cyclic-quadrilateral is equal to the opposite interior angle. |
3) ∠ECB = ∠EAD |
3) Exterior angle in a cyclic-quadrilateral is equal to the opposite interior angle. |
4) ∠E = ∠E |
4) Reflexive (common ) |
5) ΔEBC ~ ΔEDA |
5) AAA Postulate |
Circles
• Circles
• Parts of Circle
• Arc and Chords
• Equal Chords of a Circle
• Arc and Angles
• Cyclic Quadrilaterals
• Tangent to Circle
Home Page