Exterior Angle Bisector Theorem

We at ask-math believe that educational material should be free for everyone. Please use the content of this website for in-depth understanding of the concepts. Additionally, we have created and posted videos on our youtube.

We also offer One to One / Group Tutoring sessions / Homework help for Mathematics from Grade 4th to 12th for algebra, geometry, trigonometry, pre-calculus, and calculus for US, UK, Europe, South east Asia and UAE students.

Affiliations with Schools & Educational institutions are also welcome.

Please reach out to us on [email protected] / Whatsapp +919998367796 / Skype id: anitagovilkar.abhijit

We will be happy to post videos as per your requirements also. Do write to us.

Exterior angle bisector theorem : The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle.

Given : A ΔABC, in which AD is the bisector of the exterior ∠A and intersects BC produced in D.

Prove that : BD / CD = AB / AC

Construction : Draw CE || DA meeting AB in E.

Statements	Reasons
1) CE || DA	1) By construction
2) ∠1 = ∠3	2) Alternate interior angle
3) ∠2 = ∠4	3) Corresponding angle (CE ||DA and BK is a transversal
4) AD is a bisector of ∠A	4) Given
5) ∠1 = ∠2	5) Definition of angle bisector
6) ∠3 = ∠4	6) Transitivity (from 2 and 4)
7) AE = AC	7) If angles are equal then side opposite to them are also equal
8) BD / CD = BA/EA	8) By Basic proportionality theorem(EC ||AD)
9) BD /CD = AB/AE	9) BA = AB and EA = AE
10) BD /CD = AB /AC	10) AE = EC and from(7)

Examples

1) In the given figure, AE is the bisector of the exterior ∠CAD meeting BC produced in E. If AB = 10 cm, AC = 6 cm and BC = 12 cm, find CE.


Given : AB = 10 cm, AC = 6 cm and BC = 12 cm

By exterior angle bisector theorem

BE / CE = AB / AC

(12 + x) / x = 10 / 6

6( 12 + x ) = 10 x [ by cross multiplication]

72 + 6x = 10x
<
72 = 10x – 6x

72 = 4x

x = 72/4

x = 18

CE = 18 cm

2) The bisector of interior ∠A of ΔABC meets BC in D, and the bisector of exterior ∠A meets BC produced in E. Prove that BD / BE = CD / CE.

Given : In ΔABC, AD and AE are respectively the bisectors of the interior and exterior angles at A.

Prove that : BD/BE = CD/CE

Statements	Reasons
1) AD is the internal bisector of ∠A	1) Given
2) AB / AC = BD / DC	2) By Internal angle bisector theorem
3) AE is an external bisector of ∠A	3) Given
4) AB/AC = BE / CE	4) By External angle bisector theorem
5) BD / DC = BE / CE	5) From (2) and (4)
6) BD/BE = CD/CE	6) By alternendo ( a/b=c/d ⇒ a/c = b/d)

---

Similarity in Triangles

• Similarity in Geometry
• Properties of similar triangles
• Basic Proportionality Theorem(Thales theorem)
• Converse of Basic Proportionality Theorem
• Interior Angle Bisector Theorem
• Exterior Angle Bisector Theorem
• Proofs on Basic Proportionality
• Criteria of Similarity of Triangles
• Geometric Mean of Similar Triangles
• Areas of Two Similar Triangles

Home Page

Russia-Ukraine crisis update - 3rd Mar 2022

The UN General assembly voted at an emergency session to demand an immediate halt to Moscow's attack on Ukraine and withdrawal of Russian troops.