Enter the coefficients for the
Axwhere ^{2} +
Bx + C = 0 A is the coefficient of x^{2}, B is a coefficient of x and C is a constant term of the equation.Quadratic Equation will output the solutions (give you the root of the equation) (if they are not imaginary).
If A=0, the equation is not quadratic. |

(real and equal roots )

2) If b

3) If b

b

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1) x

x

Here, a = 1, b = -4 and c = 2

Discriminant = D = b

= (-4)

= 16 - 8

= 8

_______________________________________________________________

2) 3x

3x

Here, a = 3, b = 2 and c = -1

Discriminant = D = b

= (2)

= 4 + 12

= 16

________________________________________________________________

Find the roots using quadratic formula 2 m

So plug in these values in the formula, we get

-2 ± √[2

x = --------------------------

2(2)

-2 ± √[4 + 96]

x = -----------------------

4

-2 ± √ 100

x = -----------------

4

-2 ± 10

x = --------

4

- 2 + 10 -2 -10

x = ------ x = ------

4 4

x = 8/4 x = -12/4

x = 2 or x = -3 are the roots of the given equation.

2) Solve : x

a= 1, b = 4 and c =3

Using quadratic formula,

-4 ± √[4

x = --------------------------= ---------

2(1) 2

-4 + 2 -4 - 2

x = ------ or x = ------

2 2

The roots are { -1,-3}

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• Splitting of middle term

• Completing square method

• Factorization using Quadratic Formula

• Solved Problems on Quadratic Equation

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