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Find Area of Triangle
Δ = 1/2.bc. SinA = 1/2 ac.SinB = 1/2 ab.Sin C Proof : Let ABC be a triangle, then there are three cases,
Similarly, we can prove that Δ = 1/2.bc. SinA = 1/2 ab.Sin C Examples on to find area of triangle1) Find the area of the triangle ABC, in which $\angle$A = 60, b= 4 cm andc = $\sqrt{3}$ cm. Solution : The area of ΔABC is given by, A(ΔABC) = $\frac{1}{2}.bc. Sin A$ = $\frac{1}{2}.4\sqrt{3}. Sin 60$ = $2\sqrt{3}. \frac{\sqrt{3}}{2}$ A(ΔABC) = 3 sq.cm 2) Farmer Jones owns a triangular piece of land.The length of the fence AB is 120 m. The length of the fence BC is 230 m. The angle between fence AB and fence BC is 125º.How much land does Farmer Jones own? Solution : To know that how much land Jones owns for that we will draw the obtuse triangle ABC, mentioned all the given information and then use the formula to find area of triangle using trigonometry. AB = c = 120 m BC = a = 230 m $\angle$ B = 125$^{0}$ The area of ΔABC is given by, A(ΔABC) = $\frac{1}{2}.ac. Sin B$ = $\frac{1}{2}.(120).(230). Sin 125$ = 13800. (0.819152) A(ΔABC) = 11304.2976 sq.cm A(ΔABC) = 11304.30 sq.cm precalculus Home Covid19 has led the world to go through a phenomenal transition . Elearning is the future today. Stay Home , Stay Safe and keep learning!!! Covid19 has affected physical interactions between people. Don't let it affect your learning.
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