# Finding CP  when SP and Profit or Loss Percent are given

We at ask-math believe that educational material should be free for everyone. Please use the content of this website for in-depth understanding of the concepts. Additionally, we have created and posted videos on our youtube.

We also offer One to One / Group Tutoring sessions / Homework help for Mathematics from Grade 4th to 12th for algebra, geometry, trigonometry, pre-calculus, and calculus for US, UK, Europe, South east Asia and UAE students.

Affiliations with Schools & Educational institutions are also welcome.

Please reach out to us on [email protected] / Whatsapp +919998367796 / Skype id: anitagovilkar.abhijit

We will be happy to post videos as per your requirements also. Do write to us.

Finding CP when SP and Profit or Loss Percent are given

Examples on finding cp when sp and profit or loss percent are given :

1) A man sells his scooter for $18000 making a profit of 20%. How much did the scooter cost him? Solution: Let c.p =$100

As there is profit % as 20 so s.p = 100 + 20 = $120 Let the c.p of the scooter be$x

Now make proportions as

100/x = 120/18000

Cross multiply

120x = 100 . 18000

120x = 1,800,000

So, x = 1,800,000/120

x = $15000 Hence the cost price of the scooter is$15000.

_________________________________________________________________
2) By selling an AC for $20,000, I lose 20%. What did I pay for it? Solution: We have S.P. =$ 20,000 and loss = 20%.

Let c.p = $100 As there is loss % as 20 so s.p = 100 - 20 =$80

Let the c.p of the scooter be $x Now make proportions as 100/x = 80/20,000 Cross multiply 80x = 100 . 20,000 80x = 2,000,000 So, x = 2,000,000/80 x =$ 25000

Hence the cost price of the AC is $25,000. ________________________________________________________________ 3) SP =$450 and profit % = 50, find CP.

Solution :
Let c.p = $100 As there is profit % as 50 so s.p = 100 + 50 =$150

Let the c.p of the scooter be $x Now make proportions as 100/x = 150/450 Cross multiply 150x = 100 . 450 150x = 45,000 So, x = 45,000/150 x =$300

Hence, CP = $300 ______________________________________________________________ 4) A shopkeeper sells one transistor for$ 840 at a gain of 20% and another for $960 at a loss of 4%. His total gain or loss percent is:  1st Transistor Let c.p =$100 As there is profit % as 20 so s.p = 100 + 20 = $120 Let the c.p of the scooter be$x Now make proportions as 100/x = 120/840 Cross multiply 120x = 100 . 840 120x = 84,000 So, x = 84,000/120 x = $700 Hence, CP =$700 2nd Transistor Let c.p = $100 As there is loss % as 4 so s.p = 100 - 4 =$96 Let the c.p of the scooter be $x Now make proportions as 100/x = 96/960 Cross multiply 96x = 100 . 960 96x = 96,000 So, x = 96,000/96 x =$1000 Hence, CP = $1000 ∴ Total CP = 700 + 1000 =$1700
Total SP = 840 + 960 = $1800 Profit = SP - CP Profit = 1800 -1700 =$100
Profit % = (Profit/CP )x100
Profit % = (100/1700)x100
Profit % = 5.88%
Profit and Loss

Finding profit or loss percent
Finding cp when sp and Profit or Loss percent are given
Finding sp when cp and Profit or Loss percent are given
Solved examples on Profit and Loss