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11th Grade Math
Finding Profit or Loss Percent
On finding profit or loss percent we use the following formula:-
Profit % = P % = (Profit / C.P ) x 100
Loss % = L % = ( Loss /C.P )x 100
Where, P% = Profit percent
P = Profit
C.P. = Cost Price
L % = Loss per cent
L = Loss
Examples on finding profit or loss percent
1) Find the gain or loss percent, if
C.P. = $ 4oo , S.P. = $ 500
We have, C.P. = $ 400 and S.P. = $ 500.
Since, S.P. > C.P.
Therefore, there is gain or profit.
Profit = S.P. – C.P.
= $500 - $400 = $100
∴ Profit per cent = Profit / C.P. x 100
= 100 / 400 x 100
2) C.P. = $ 200 , S.P. = $ 150
Since, C.P. = $ 200 and S.P. = $ 150.
As c.p > s.p so there is loss.
Loss = C.P. – S.P.
= $ 200 - $ 150
= $ 50
∴ Loss per cent = Loss / C.P. x 100
= 50 / 200 x 100
3) A box of Alphonso mangoes was purchased by a fruit – seller for $300. However, he had to sell them for $250 because they began they began to overripe. What was the loss percentage?
We have, C.P. = $ 300 and S.P. = $ 250
Since, C.P. > S.P. there is loss
∴ Loss = C.P. – S.P. = $ 300 – 250
= $ 50
Now, Loss % = Loss / C.P. x 100
= 50 / 300 x 100 = 16.67 %
Hence, 16.67% loss
4) Harry bought a computer for $1200 and spent $200 on its accessories. He sold it for $ 1680. Find his profit or loss. What was his profit or loss per cent?
Cost of the computer after accessories = $( 1200 + 200) = $ 1400
S.P = $ 1680
S.P > C.P so there is a profit.
Profit = P = S.P – C.P
P = 1680 -1400
P = $ 280
Profit % = ( P / C.P ) x 100
P % = ( 280 / 1400 ) x 100
P % = 20 %
5) By selling a coat for $ 630, a shopkeeper earns a profit of 5%. Find the cost price of coat.
Here, S.P = $ 630 , P% = 5 % and C.P = ?
Let C.P = 100
S.P = 100 + 5 ( As there is P%, so add P% + 100 )
S.P = $ 630 ( given)
---- = ------ ( cross multiply)
105 x C.P = 630 x 100
105 x C.P = 63,000
C.P = 63,000/ 105
C.P = $600
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