# One-to one function

A function f: A → B is said to be one-to one function if

f ( a _{ 1} ) = f (a _{ 2} )

⇒ ( a _{ 1} ) = ( a _{ 2} ), ( a _{ 1} )( a _{ 2} ) ∈ A

Let A = {( a _{ 1} )( a _{ 2} )( a _{ 3} )( a _{ 4} )}
and B = {( b _{ 1} )( b _{ 2} )( b _{ 3} )( b _{ 4} )}

**Example :** – Determine if the function given below is one to one.

1) To each state of India assign its Capital

**Solution:** This is not one to one function because each state of India has different capital.

2) Function = {(2,4),(3,6),(-1,-7)}

**Solution : ** The above function is one to one because each value of range has different value of domain.

3) f(x) = |x|

**Solution : ** Here to check whether the given function is one to one or not, we will consider some values of x (domain) and from the given function find the value of range(y).

From the above table we can see that an element in the range repeats, then this is not a 1 to 1 function.
**How to determine one-to one function from the graph?**

Q.1 State which of the following graph shows one to one function and why?
Note : For checking 1-to-1 function on the graph, we will use a horizontal test.

**Horizontal test : Draw a horizontal line on the graph, if that line cuts the graph in two points then the given graph is not 1-to-1 graph.**

**Solution :** In the 1st graph if we draw a horizontal line then that line cuts the graph at one point only so the 1st graph is 1-to-1 function graph.

In the 2nd graph if we draw a horizontal line then that line cuts the graph at one point only so the 2nd graph is 1-to-1 function graph.

In the 3rd graph if we draw a horizontal line then that line cuts the graph at two points so the 3rd graph is not 1-to-1 function graph.

Q.2 Show that the given function (x+2)/(x-3) = (y+2)/(y-3) is one-to one function.

**Solution : ** (x+2)/(x-3) = (y+2)/(y-3)

(x+2 )(y-3) = (y+2)(x-3) ----(cross multiply)

⇒ xy -3x + 2y - 6 = xy -3y + 2x - 6

⇒ -3x + 2y = -3y + 2x -----( xy and -6 get cancelled out)

⇒ -3x -2x = -3y - 2y ----( bring the like terms together)

⇒ -5x = -5y

⇒ x = y ----( divide both side by negative 5)

So the given function is one-to one function.

11th grade math

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