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Solved Example

1.

In the above example, we saw that 90 is a product of multiplication between the prime numbers – 2, 3 and 5. Hence, finding 2, 3, and 5 as the numbers responsible for the product number 90 is known as prime factorization. This way of illustrating prime factorization is known as ‘factor tree’.

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2. Let’s take some more examples to clarify the concept.

Let’s take the number 36.

We will begin the factorization with the lowest prime number 2.

36/2 = 18.

Since, 18 is an even number we will further divide 18 by 2, i.e.

18/2 = 9. Now, 9 is not divisible by 2, so we move on to the next prime number 3, and divide the number with 3, i.e.

9/3 = 3.

Thus, the prime factorization of number 36 = 2 x 2 x 3 x 3.

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3. Let’s take the number 980.

We will begin the factorization with the lowest prime number i.e. 2.

So, 980/2 = 490. We will again divide 490 by 2 as 490 is an even number, and that gives us the result

490/2 = 245. Applying the divisibility rule of the next prime number i.e. 3, we get that 245 is not divisible by 3 and we move on to the next prime number 5.

245/5 = 49 gives us the answer 49. Moving on to the next prime number 7, we will see that

49/7 = 7, and we stop here.

Hence we come to know that – 980 = 2 x 2 x 5 x 7 x 7

1. Factorize 2364 using the factor tree method of prime factorization.

2. Factorize 7335 using the factor tree method of prime factorization.

3. Factorize 44230 using the factor tree method of prime factorization.

4. Factorize 34 using the factor tree method of prime factorization.

5. Factorize 188 using the factor tree method of prime factorization.

6. Factorize 655 using the factor tree method of prime factorization.

7. Factorize 3494 using the factor tree method of prime factorization.

8. Factorize 8984 using the factor tree method of prime factorization.

9. Factorize 10002 using the factor tree method of prime factorization.

10. Factorize 9980 using the factor tree method of prime factorization.

Prime factorization to 6th grade math

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