# Theorems on Arc and Angle

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The following are circle theorems on arc and angle.
The Arc and Angle means the angle is subtended in the given arc.

Theorems on Arc and Angle

1) The angle subtended by an arc of a circle at the center is double the angle subtended by it at any point on the remaining part of the circle.
Given : Arc PQ of a circle C(O, r) and point r on the remaining part of the circle.
Prove that: ∠ POQ = 2∠PRQ
Construction: join RO and produce it to point M outside the circle. Case 1: When arc PQ is a minor arc (figure (i))
 Statements Reasons 1) ∠POM = ∠OPM + ∠ORP 1) By exterior angle theorem (∠POM is exterior angle) 2) OP = OR 2) Radii of same circle 3) ∠OPR = ∠ORP 3) In a Δ two sides are equal then the angle opposite to them are also equal. 4) ∠POM = ∠ORP + ∠ORP 4) Substitution property. From (1) 5) ∠POM = 2∠ORP 5) Addition property.

Similarly, when ∠QOM is an exterior angle then ∠QOM = 2∠ORQ
∴ from above, ∠POQ = 2∠PRQ

Case 2: When arc PQ is a semicircle.[figure(ii)]
 Statements Reasons 1) ∠POM = ∠OPR + ∠ORP 1) Exterior angle theorem. 2) ∠POM = ∠ORP + ∠ORP 2) As,OP = OR = radius. ∴∠ORQ = ∠ORP 3) ∠POM = 2∠ORP 3) Substitution and addition property. 4) ∠QOM = ∠ORQ + ∠OQR 4) Exterior angle theorem. 5) ∠QOM = ∠ORQ + ∠ORQ 5) As, OQ =OR = radius, ∴ ∠ORQ = ∠OQR 6) ∠QOM = 2∠ORQ 6) Substitution and addition property.

∴ From above, ∠POQ = 2∠PRQ

Case 3: When arc PQ is a major arc.[figure(iii)]
 Statements Reasons 1) ∠POM = ∠OPR + ∠ ORP 1) By exterior angle theorem. 2) ∠POM = 2∠ORP 2) As, OP = OR = radius, ∴∠OPR = ∠ORP and by addition property 3) ∠ QOM = ∠ORQ + ∠OQR 3) By exterior angle theorem in ΔQOR 4) ∠QOM = 2∠ORQ 4) As, OP = OR = radius, ∴∠ORQ = ∠OQR and by addition property 5) ∠POM + ∠QOM = 2(∠ORP + ∠ORQ) 5) From (2) and (4) 6) Reflex ∠POQ = 2∠PRQ 6) Reflex of ∠POQ =∠POM + ∠QOM
2) The angle in a semicircle is a right angle.
Given : PQ is a diameter of the circle. ∠PRQ is an angle in a semicircle.
Prove: ∠PRQ = 90° Statements Reasons 1) ∠POQ = 2∠PRQ 1) Angle subtended by an arc of a circle at its center is twice the angle formed by the same arc. 2) 180 0 = 2∠PRQ 2) As POQ is a straight line 3) ∴ ∠PRQ = 90 0 3) Division property
So the angle in a semicircle is a right angle.
Theorems on Circle

Theorems on Chord
Theorems on Chord and Subtended Angle
Theorems on Arc and Angle