Theorems on Chord and Subtended Angle
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Here we will discuss some theorems on chord and subtended angle.In this Circle -Theorems, the theorems are based on equal chord. Here, we shall also study theorems on subtended angles and the relationship between the lengths of chords and their distances from the center of the given circle.
Theorems on Chord and Subtended Angle
1) Equal chords of a circle are equidistant from the center.
Given : Two chords AB and CD of circle C(O,r) such that
AB = CD and OL ⊥ CD.
Prove that : Chords AB and CD are equidistant from the center
i.e. OM = OL
Construction : Join OA and OC.
| 1) OL ⊥ AB ⇒ AL = 1/2AB | 1) OM ⊥ CD ⇒ CM = 1/2CD |
| 2) AB = CD | 2) Given |
| 3) 1/2 AB = 1/2 CD | 3) Given |
| 4) AL = CM | 4) From AB = CD |
| 5) OA = OC | 5) Equal radius of the circle |
| 6) AL = CM | 6) From (4 ) |
| 7) ∠ALO = ∠CMO | 7) Each 900 |
| 8) OL = OM | 8) CPCTC |
Given : AB = CD
Prove that : ∠AOB = ∠COD
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| 1) AB = CD | 1) Given |
| 2) OA = OC | 2) Radius of same circle |
| 3) OB = OD | 3) Radius of same circle |
| 4) ΔAOB = ΔCOD | 4) SSS Postulate |
| 5) ∠AOB = ∠COD | 5) CPCTC |
3) Angles in the same segment of a circle are equal.
Given: A circle C(O,r), an arc PQ and two angles ∠PRQ and ∠PSQ
in the same segment of the circle.
Prove: ∠PRQ = ∠PSQ
Construction: Join OP and OQ.
| |
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| 1) ∠POQ = 2∠PRQ | 1) Given |
| 2) ∠POQ = 2∠PSQ | 2) Given |
| 3) 2∠PRQ = 2∠PSQ | 3) From (1) and (2) |
| 4) ∴ ∠PRQ = ∠PSQ | 4) From (3) |
| 5) Reflex ∠POQ = 2∠PRQ and Reflex ∠POQ = 2∠PSQ | 5) From the diagram |
| 6) 2∠PRQ = 2∠PSQ | 6) From the diagram |
| 7) ∠PRQ = ∠PSQ | 7) From (6) |
Theorems on Circle
• Theorems on Chord
• Theorems on Chord and Subtended Angle
• Theorems on Arc and Angle
• Theorems on Cyclic Quadrilateral
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