Slope Intercept Form of a Line
Slope Intercept Form of a Line

Vertex form from Quadratic Equation

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In this section, you will learn the vertex form from quadratic equation. Using this we can graph it easily. The quadratic equation gives us the parabolic graph.

The equation of a parabola can be expressed in either standard or vertex form from quadratic equation as shown in the picture below.

Standard form Vertex form
y = ax2 + bx + c f(x) = a(x –h )2 +k

Standard form:

The standard form of a parabola's equation is generally expressed:
y = ax2 + bx + c

Importance of ‘a’
1) If a > 0 then the parabola open upwards.( ∪)
2) If a < 0 then the parabola open downwards (∩)
3) If |a | > 1 then parabola stretches sideways.
4) If | a| < 1 then parabola is narrower.

To find x – coordinate of vertex of parabola is

x = h = - b/ 2a

After finding the x coordinate put that value in the given equation to find the y coordinate of vertex (k)
x = h is the axis of symmetry.

Standard form Vetex form
y = ax2 + bx + c f(x) = a(x –h )2 +k

Vertex form :

The vertex form of a parabola's equation is generally expressed as :
y = a (x – h )2 + k
Where (h,k) are the coordinates of vertex.

Vetex form
f(x) = a(x –h )2 +k

Importance of ‘a’
1) If a > 0 then the parabola open upwards.( ∪)
2) If a < 0 then the parabola open downwards (∩)
3) If |a | > 1 then parabola stretches sideways.
4) If | a| < 1 then parabola is narrower.


Example 1: Write the coordinates of vertex and shape of the parabola of equation y = 2x2+ 4x - 6

Solution :
y = 2x2+ 4x - 6

a = 2, b = 4 and c= -6

As a > 0 the parabola will open upward (∪)

X-coordinate = -b/2a

= -4/(2 x2) = -4/4 = -1

Y-coordinate = f(-1) = 2(-1)2 +4(-1) - 6

= 2 - 4 -6

= -8

Coordinates of Vertex = (-1,-8)

Axis of symmetry = x = -1


Introduction of Quadratic Equations

Splitting of middle term
By completing the square
Factorization using Quadratic Formula
Vertex form from Quadratic Equation
Finding Axis of Symmetry in Quadratic equation
Solved Problems on Quadratic Equation

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