# Volume of Irregular Shape

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The volume of irregular shape is calculated by number of blocks present in it.

Example 1: Find the volume of the above shape considering that each side is of length 1unit.
Solution : Count the number of blocks.
1st layer = 5
2nd layer = 5
3rd layer = 2
4th layer = 2
5th layer = 2
6th layer = 2
∴ Volume = 5 + 5 + 2 + 2 + 2 + 2 = 18 cu.units.
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Example 2: Find the volume of the above shape considering that each side is of length 1unit.
Solution : Count the number of blocks.
1st layer = 4
2nd layer = 2
∴ Volume = 4 + 2 = 6 cu.units
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Example 3: Find the volume of the above shape considering that each side is of length 1unit.
Solution : Count the number of blocks.
1st layer = 1
2nd layer = 3
3rd layer = 4
4th layer = 6
∴ Volume = 1 + 3 + 4 + 6 = 14 cu.units.
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Example 4: Find the volume of the above shape considering that each side is of length 1unit.
Solution : Count the number of blocks.
1st layer = 5
2nd layer = 12
∴ Volume = 5 + 12 = 17 cu. Units.
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Example 5: Find the volume of the above shape considering that each side is of length 1unit.
Solution : Count the number of blocks.
1st layer = 1
2nd layer = 1
3rd layer = 1
4th layer = 4
∴ Volume = 1 + 1 + 1 + 4 = 7 cu. Units.

Volume :

Volume Formulas
Volume of Irregular Shape
Volume of Cube
Volume of Rectangular Prism(Cuboid)
Volume of Cylinder
Volume of Cone
Volume of Sphere
Volume of Hemisphere
Volume of Prism
Volume of Pyramid

From Irregular Shape to Mensuration